Chapter 3 · Basic Biomedical Engineering · ~38 min read

Bio-fluid Mechanics

6 blueprint items · MoE Revised Blueprint 2016 E.C

1. Chapter Overview

Bio-fluid mechanics applies the conservation laws of classical fluid mechanics to biological systems — primarily blood flow in the cardiovascular system, air flow in the respiratory tract, and joint lubrication. For the BME exit exam, this chapter is weighted at 6 blueprint items under the Basic BME (20%) theme. Exam items cluster around a small set of high-yield equations and qualitative cardiovascular facts rather than advanced computational fluid dynamics.

This section highlights concepts that frequently appear on exit exams. The pattern is clear: confusion between viscosity factors and Poiseuille resistance factors, misapplication of Bernoulli vs continuity, and mixing cardiovascular physiology (stroke volume, venous return) with pure fluid mechanics.

This chapter is organized to close those gaps systematically. Sources include AAiT lecture extracts (telegram-b2-biofluid-chapter-*.json), Biofluid Mechanics in Cardiovascular Systems (Lee & Waite), Biofluid Mechanics and Biotransportation course notes, and the JU mock exit exams (2023–2024 tutorial Q&A).

What the blueprint expects you to do:

  1. Define fluid properties and distinguish Newtonian from non-Newtonian blood rheology.
  2. Apply continuity, Bernoulli, Poiseuille, and Reynolds number to numerical and conceptual problems.
  3. Explain how arteries, capillaries, and veins differ in velocity, pressure, and driving forces.
  4. Connect fluid mechanics to clinical tools: Gorlin equation for stenotic valves, surfactant in alveoli, wall shear stress and atherosclerosis.

2. Learning Outcomes

After completing this chapter, you should be able to:

  1. Describe the historical development of cardiovascular fluid mechanics from Hippocrates and Harvey to Poiseuille and Reynolds.
  2. Define density, dynamic viscosity, kinematic viscosity, pressure, and shear stress; state SI units for each.
  3. Distinguish Newtonian fluids (water, plasma) from non-Newtonian blood; identify the Casson model and Fåhræus–Lindqvist effect.
  4. Apply the continuity equation for incompressible flow: A1v1=A2v2A_1 v_1 = A_2 v_2.
  5. Apply Bernoulli's equation and explain when viscous losses invalidate the ideal form.
  6. Calculate Reynolds number and classify flow as laminar, transitional, or turbulent.
  7. Apply Poiseuille's law and the electrical analogy Q=ΔP/RQ = \Delta P / R to blood vessels.
  8. Explain cardiovascular flow distribution: highest velocity in arteries, lowest in capillaries, venous return mechanisms.
  9. Use the Gorlin equation conceptually to determine what valve area represents clinically.
  10. Solve exam-style calculation problems involving branching (aorta → iliac), constriction, and pressure–velocity trade-offs.

3. Core Concepts

3.1 What Is a Fluid?

A fluid is a substance that deforms continuously under any shear stress, no matter how small. Solids resist shear statically and may recover their shape; fluids flow until the stress is removed.

PropertySolidFluid
Response to shearFixed deformation possibleContinuous deformation
Shape recoveryPartial or fullNever regains original shape
Static shear resistanceYesNo

Bio-fluid relevance: ~65% of the human body is water. Blood, lymph, synovial fluid, cerebrospinal fluid, and respiratory gases all obey fluid mechanics principles. Joint lubrication and pulmonary gas exchange are direct bio-fluid applications.

3.2 Liquids vs Gases

PropertyLiquidGas
CompressibilityNearly incompressibleHighly compressible
VolumeFixed volume, takes container shapeExpands to fill container
Free surfaceYes (if not filling container)No
CohesionStrongWeak

Blood and water are treated as incompressible in most cardiovascular calculations (ρ1060\rho \approx 1060 kg/m³). Air in the trachea and bronchi is compressible at high flow rates but often approximated as incompressible in physiological breathing.

3.3 Internal vs External Flow

  • Internal flow: Fluid completely bounded by solid surfaces — blood in arteries, air in bronchi, IV fluid in tubing.
  • External flow: Unbounded fluid moving over a surface — air over an airplane wing, blood swirling past a stenotic valve leaflet (local external flow at the obstruction).

Exam tip: Poiseuille's law applies to internal laminar flow in circular tubes. Bernoulli applications include both (venturi meters internally; lift on wings externally).

3.4 Density, Specific Weight, and Specific Gravity

Density ρ\rho = mass per unit volume (kg/m³).

\rho = \frac{m}{V} Typical values: water = 1000 kg/m³; blood ≈ 1060 kg/m³; air ≈ 1.23 kg/m³. **Specific weight** $\gamma = \rho g$ (N/m³). **Specific gravity** = ratio of substance density to water density at 4°C (dimensionless). **Worked mini-example:** Oil mass 825 kg, volume 0.917 m³.

\rho = \frac{825}{0.917} = 900 \text{ kg/m}^3,\quad \gamma = 900 \times 9.81 = 8829 \text{ N/m}^3,\quad SG = \frac{900}{998} \approx 0.90

3.5 Pressure

Pressure is normal force per unit area exerted by a fluid on a surface:

P = \frac{F}{A} \quad [\text{Pa} = \text{N/m}^2] In a static fluid, pressure acts perpendicular to any surface. Atmospheric pressure ≈ 101.3 kPa = 1 atm. **Hydrostatic pressure** increases with depth: $\Delta P = \rho g h$. Clinical units: **mmHg** (1 mmHg ≈ 133 Pa). Normal adult arterial blood pressure ≈ **120/80 mmHg** (systolic/diastolic).

3.6 Viscosity and Newton's Law

Dynamic viscosity μ\mu quantifies resistance to shear deformation.

Newton's law of viscosity (Newtonian fluids):

\tau = \mu \frac{du}{dy} where $\tau$ = shear stress (N/m²), $du/dy$ = shear rate (s⁻¹). Units: N·s/m² = Pa·s = kg/(m·s). Typical values: water ≈ 1.14×10⁻³ Pa·s; whole blood ≈ 3–4×10⁻³ Pa·s (shear-dependent).

Kinematic viscosity:

ν=μρ[m2/s]\nu = \frac{\mu}{\rho} \quad [\text{m}^2/\text{s}]

Factors affecting viscosity (fluids in general):

Affects viscosityDoes NOT affect viscosity
TemperatureVelocity
Composition/concentrationVessel length
Attractive forces between moleculesPipe diameter
Pressure (minor, gases)Flow rate

Exam trap: Velocity appears in Reynolds number and Bernoulli — it does not change intrinsic fluid viscosity. Vessel length affects resistance (Poiseuille), not viscosity.

3.7 Newtonian vs Non-Newtonian Fluids

TypeBehaviorExamples
Newtonianμ\mu constant; τ\tau \propto shear rate linearlyWater, air, plasma
Pseudo-plastic (shear-thinning)Apparent μ\mu decreases as shear rate increasesBlood, latex paint
Dilatant (shear-thickening)Apparent μ\mu increases with shear rateQuicksand, cornstarch slurry
Bingham plasticYield stress before flowToothpaste, mayonnaise
ThixotropicViscosity depends on time of shear (history-dependent)Some gels, ketchup

Blood is non-Newtonian primarily because of red blood cells (~45% hematocrit). At low shear, RBCs aggregate (rouleaux) → high apparent viscosity. At high shear in arterioles, cells align and disaggregate → lower apparent viscosity.

The Casson model describes blood rheology with yield stress — exam answer for "which model describes non-Newtonian blood behavior."

Fåhræus–Lindqvist effect: In tubes smaller than ~300 µm, apparent blood viscosity decreases as diameter decreases. Explained by RBC axial migration toward the vessel center, leaving a cell-free plasma layer near the wall. This is distinct from the Fåhræus effect (hematocrit decreases in small vessels).

3.8 Conservation of Mass — Continuity Equation

For steady flow with no sources or sinks:

m˙in=m˙out\dot{m}_{in} = \dot{m}_{out}

For incompressible flow (ρ\rho = constant):

Q=A1v1=A2v2=constantQ = A_1 v_1 = A_2 v_2 = \text{constant}

Volume flow rate QQ (m³/s). Textbooks often use QQ or V˙\dot{V}.

Physical meaning: "The water all has to go somewhere." Where the pipe is wider, flow is slower (at constant QQ).

Branching (aorta → iliac): At a bifurcation with steady incompressible flow: Q_{parent} = Q_{branch1} + Q_{branch2}

A_{parent} v_{parent} = A_1 v_1 + A_2 v_2

3.9 Bernoulli's Equation

Derived from conservation of energy along a streamline (ideal, inviscid, steady, incompressible): P_1 + \frac{1}{2}\rho v_1^2 + \rho g h_1 = P_2 + \frac{1}{2}\rho v_2^2 + \rho g h_2

Key insight: As speed increases, pressure decreases (when height is constant).

Applications:

  • Torricelli's theorem (tank drain speed)
  • Venturi meter (flow measurement from ΔP\Delta P)
  • Airplane wing lift
  • Stenotic arteries: Blood speeds through constriction → lateral pressure drops → risk of collapse or reduced perfusion downstream
  • Doppler echocardiography estimates pressure gradient from velocity: ΔP12ρv2\Delta P \approx \frac{1}{2}\rho v^2 (simplified Bernoulli)

Losses intuition: Real flows have viscous losses (friction), turbulence, and separation at stenoses. Bernoulli overpredicts downstream pressure recovery. The Gorlin equation uses an empirical constant KK to account for these non-ideal effects at heart valves.

Modified Bernoulli with head loss hLh_L:

P1ρg+v122g+z1=P2ρg+v222g+z2+hL\frac{P_1}{\rho g} + \frac{v_1^2}{2g} + z_1 = \frac{P_2}{\rho g} + \frac{v_2^2}{2g} + z_2 + h_L

3.10 Poiseuille's Law

For laminar, fully developed, Newtonian flow in a straight circular tube:

Q=πr4ΔP8μL=ΔPRQ = \frac{\pi r^4 \Delta P}{8 \mu L} = \frac{\Delta P}{R}

Hydrodynamic resistance:

R=8μLπr4R = \frac{8 \mu L}{\pi r^4}

Critical relationships for exams:

Parameter changeEffect on QQ (fixed ΔP\Delta P)
Radius doublesQQ increases 16× (r4r^4)
Length doublesQQ halves
Viscosity doublesQQ halves
ΔP\Delta P doublesQQ doubles

Ohm's law analogy (circulation):

Q=ΔPRQ = \frac{\Delta P}{R}

Same form as electrical I=V/RI = V/R. Blood flow is driven by the pressure gradient (heart pump creates ΔP\Delta P); resistance is set by vessel geometry and blood viscosity.

3.11 Reynolds Number

Re=ρVDμ=inertial forcesviscous forcesRe = \frac{\rho V D}{\mu} = \frac{\text{inertial forces}}{\text{viscous forces}}

For pipe flow:

RegimeReynolds number
LaminarRe < 2300
Transitional2300 < Re < 4000
TurbulentRe > 4000

Blood flow context:

LocationApproximate Re
Brain capillaries~10²
Aorta~10³
Retinal arteriole (example)< 1 (definitely laminar)

Most physiological blood flow is laminar (Re ~ 300 or less). Turbulence occurs in pathological conditions (stenotic valves → murmurs) or extreme athletic output in the descending aorta.

No-slip condition: Fluid velocity relative to a solid boundary is zero at the wall. Fluid particles adhere to the surface — they do not slip past it.

3.12 Cardiovascular Applications

Arteries

  • Carry blood away from the heart (except pulmonary arteries).
  • Highest blood velocity in the circulation (large QQ, moderate area).
  • Thick, elastic walls withstand high pressure.
  • Aorta radius ~10 mm; blood speed ~0.3 m/s.
  • Flow generally laminar under normal conditions.

Aorta branching: The abdominal aorta bifurcates into left and right common iliac arteries. Continuity requires parent flow equals sum of branch flows. If symmetric bifurcation with equal branch areas, each iliac carries ~50% of cardiac output.

Capillaries

  • Largest total cross-sectional arealowest velocity (~0.5 mm/s).
  • Thin walls optimized for exchange (diffusion, filtration).
  • Effective capillary area from continuity: if aorta RA=10R_A = 10 mm, vA=0.3v_A = 0.3 m/s, vC=5×104v_C = 5 \times 10^{-4} m/s, then AC=πRA2(vA/vC)0.20A_C = \pi R_A^2 (v_A/v_C) \approx 0.20 m².

Veins

  • Carry blood toward the heart.
  • Low pressure, thin walls, valves prevent backflow.
  • Driving forces for venous return: skeletal muscle pump, respiratory pump, venous tone — not primarily the heart's pressure (heart drives arterial side).
  • Exam answer "main driving force in veins" often includes skeletal muscle contraction or "all of the above" (gravity, muscle pump, cardiac suction).

Pressure and Flow Summary

Vessel typeRelative velocityRelative pressureWall characteristics
ArteriesHighestHighestThick, elastic
ArteriolesModerateDrops sharplySmooth muscle (resistance vessels)
CapillariesLowestLowSingle endothelial layer
VeinsLow–moderateLowestThin, valves

Stroke volume (SV): Blood ejected per ventricular beat (~70 mL).

Cardiac output (CO): CO=HR×SVCO = HR \times SV (~5 L/min at rest).

3.13 Gorlin Equation (Heart Valves)

Used to estimate effective valve area in stenosis:

AV=COHR×TE×KΔPA_V = \frac{CO}{HR \times T_E \times K \sqrt{\Delta P}}

where COCO = cardiac output, HRHR = heart rate, TET_E = ejection time, ΔP\Delta P = mean pressure gradient (mmHg), KK = empirical Gorlin constant (~44.3 aortic, ~37.7 mitral).

Derived from Bernoulli + continuity with empirical correction for viscous losses and vena contracta.

Factors affecting calculated valve area: pressure gradient, flow rate (CO), heart rate, ejection time — not valve type directly in the formula (type affects KK).

3.14 Respiratory Fluid Mechanics (Brief)

Surfactant (pulmonary) reduces alveolar surface tension → prevents alveolar collapse during expiration (Laplace law: P=2γ/rP = 2\gamma/r).

Airway resistance follows Poiseuille principles; laminar flow in small bronchioles, transitional/turbulent in trachea during high flow.

3.15 Wall Shear Stress and Atherosclerosis

τw=μdudywall\tau_w = \mu \frac{du}{dy}\bigg|_{wall}

Low or oscillating shear at bifurcations promotes atherosclerotic plaque formation. Shear rate is the rheological factor most linked to plaque growth in exam questions.

3.16 History of Bio-fluid Mechanics (Blueprint)

Understanding the historical arc helps anchor conceptual questions that appear as "who discovered" or "what did Harvey prove" style items.

Ancient foundations. Huang Ti (~2700 BC, China) wrote early texts on circulation. Hippocrates (~400 BC) separated medicine from magic and treated the body as part of nature to be understood systematically. Aristotle (384–322 BC) identified the heart as the center of blood vessels but did not distinguish arteries from veins. Praxagoras of Cos was among the first to differentiate arteries (thought to carry air) from veins (carriers of blood) and described the pulse.

Harvey's revolution (1628). William Harvey's An anatomical study of the motion of the heart and of the blood of animals demonstrated that blood is pumped by the heart and recirculates — it is not consumed as fuel after being made in the liver. His quantitative argument: cardiac output in minutes exceeds total blood volume, proving recirculation. This is the foundational concept linking the heart as a pump to all subsequent fluid mechanics of circulation.

Poiseuille (1838). Jean Louis Marie Poiseuille, a French physician-physicist, experimentally derived the law relating flow rate to pressure drop, viscosity, and tube geometry in capillary tubes — directly motivated by blood flow in small vessels.

Frank (1890). Otto Frank published the fundamental form of the arterial pulse and advanced pressure measurement technology (optical manometers). Frank's work bridges fluid mechanics and cardiovascular physiology — the arterial system as a Windkessel (elastic reservoir).

Reynolds (1883–1895). Osborne Reynolds identified the dimensionless ratio governing laminar–turbulent transition, essential for predicting when blood flow departs from orderly parabolic profiles.

Modern era. Doppler ultrasound, cardiac catheterization, computational hemodynamics, and stent design all rest on these foundations. As a BME graduate, you are expected to connect Harvey's pump concept → Poiseuille resistance → Bernoulli stenosis gradients → Gorlin valve area in a single coherent clinical narrative.

3.17 Pressure Measurement in Clinical Practice

Direct measurement uses a fluid-filled catheter connected to a pressure transducer (strain gauge or piezoresistive). The catheter tip must be positioned at the point of interest (e.g., left ventricle, pulmonary artery). Advantages: accuracy, fast response for waveform analysis. Disadvantages: invasive, infection risk, vessel damage.

Indirect arterial pressure (cuff sphygmomanometry) inflates a cuff above systolic pressure, then releases. Korotkoff sounds (auscultatory method) or cuff oscillations (oscillometric devices) estimate systolic and diastolic pressure. Oscillometric monitors in ICUs often report mean arterial pressure (MAP) most reliably.

Derived pressure from velocity (Doppler/Bernoulli) estimates ΔP\Delta P across a stenosis from measured jet velocity. Simplified: ΔP4v2\Delta P \approx 4v^2 when vv is in m/s and ΔP\Delta P is in mmHg (empirical clinical shortcut from 12ρv2\frac{1}{2}\rho v^2 with blood density). Caution: pressure recovery distal to stenosis can make Doppler gradients differ from catheter gradients.

Units conversion anchors:

UnitEquivalent
1 mmHg133.3 Pa
1 atm101.3 kPa
1 atm760 mmHg
10 mmHg~1.33 kPa

4. Technical Deep Dive

4.1 Derivation Logic — Continuity

Consider a control volume in a pipe. Mass entering per unit time = ρA1v1\rho A_1 v_1. Mass leaving = ρA2v2\rho A_2 v_2. For steady state with no accumulation: ρA1v1=ρA2v2\rho A_1 v_1 = \rho A_2 v_2. If ρ\rho is constant: A1v1=A2v2A_1 v_1 = A_2 v_2.

4.2 Derivation Logic — Bernoulli

Work done by pressure forces + gravitational work = change in kinetic energy. Per unit mass along a streamline:

P1ρ+v122+gh1=P2ρ+v222+gh2\frac{P_1}{\rho} + \frac{v_1^2}{2} + g h_1 = \frac{P_2}{\rho} + \frac{v_2^2}{2} + g h_2

Multiply by ρ\rho to get pressure form.

When Bernoulli fails: Long pipes (viscous losses dominate), turbulent mixing, unsteady pulsatile flow (use Womersley number α\alpha for pulsatility), non-Newtonian blood at very low shear.

4.3 Poiseuille Derivation Sketch

For laminar flow in a cylinder, velocity profile is parabolic:

v(r) = v_{max}\left(1 - \frac{r^2}{R^2}\right),\quad v_{max} = \frac{R^2 \Delta P}{4 \mu L}

Integrating over the cross-section gives Q=πR4ΔP/(8μL)Q = \pi R^4 \Delta P / (8\mu L).

Maximum velocity in laminar tube flow: vmax=2vavgv_{max} = 2 v_{avg}.

4.4 Velocity vs Diameter at Constant Pressure Gradient

From Poiseuille: vavg=Q/(πr2)=r2ΔP/(8μL)v_{avg} = Q/(\pi r^2) = r^2 \Delta P / (8\mu L).

Therefore vavgr2v_{avg} \propto r^2 when ΔP\Delta P and LL are fixed — increasing diameter increases velocity in this scenario. Contrast with constant flow rate (continuity), where increasing diameter decreases velocity. Always note which constraint the question specifies.

4.5 Casson Model

\sqrt{\tau} = \sqrt{\tau_y} + \sqrt{\mu \dot{\gamma}} Yield stress $\tau_y$ accounts for RBC aggregation at low shear. Blood behaves nearly Newtonian above shear rates ~100 s⁻¹.

4.6 Womersley Number (Pulsatile Flow)

α=rωρμ\alpha = r\sqrt{\frac{\omega \rho}{\mu}}

Ratio of transient (inertial) to viscous forces. Human aorta α20\alpha \approx 20. Explains why arterial flow is not purely steady Poiseuille — pressure and flow are pulsatile.

4.7 Fully Worked Calculation Problems


Problem 1 — Continuity: Aorta to Capillaries

Given: Aorta radius RA=10R_A = 10 mm, blood speed vA=0.30v_A = 0.30 m/s. Mean capillary speed vC=5×104v_C = 5 \times 10^{-4} m/s. Find effective capillary cross-sectional area.

Solution:

AC=AAvAvC=πRA2vAvCAC=π(0.01)2×0.305×104=π×104×600=0.18850.19 m2A_C = A_A \frac{v_A}{v_C} = \pi R_A^2 \frac{v_A}{v_C} A_C = \pi (0.01)^2 \times \frac{0.30}{5 \times 10^{-4}} = \pi \times 10^{-4} \times 600 = 0.1885 \approx \mathbf{0.19 \text{ m}^2} ---

Problem 2 — Continuity: Aorta Bifurcation to Iliac Arteries

Given: Abdominal aorta diameter 20 mm, mean velocity 0.25 m/s. Bifurcates into two common iliac arteries, each diameter 10 mm. Assume symmetric flow split. Find velocity in each iliac.

Solution:

Q_{aorta} = A_a v_a = \frac{\pi}{4}(0.02)^2 (0.25) = 7.854 \times 10^{-5} \text{ m}^3/\text{s} Each iliac carries half: Q_{iliac} = 3.927 \times 10^{-5} \text{ m}^3/\text{s} v_{iliac} = \frac{Q_{iliac}}{A_{iliac}} = \frac{3.927 \times 10^{-5}}{\pi/4 \times (0.01)^2} = \frac{3.927 \times 10^{-5}}{7.854 \times 10^{-5}} = \mathbf{0.50 \text{ m/s}} Check: $A_a v_a = 2 A_{iliac} v_{iliac}$ → $7.85 \times 10^{-5} = 2 \times 7.85 \times 10^{-5} \times 0.5$ ✓ ---

Problem 3 — Reynolds Number: Laminar or Turbulent?

Given: Blood in 4 mm diameter tube, mean velocity 6 cm/s, μ=0.0035\mu = 0.0035 Pa·s, ρ=1060\rho = 1060 kg/m³.

Solution:

Re=ρVDμ=1060×0.06×0.0040.0035=0.25440.0035=73Re<2300laminarflow.Re = \frac{\rho V D}{\mu} = \frac{1060 \times 0.06 \times 0.004}{0.0035} = \frac{0.2544}{0.0035} = \mathbf{73} Re < 2300 → **laminar flow**. ---

Problem 4 — Wall Shear Stress

Given: Same tube as Problem 3. For laminar flow, wall shear stress:

τw=4μvavgR=8μvavgD\tau_w = \frac{4 \mu v_{avg}}{R} = \frac{8 \mu v_{avg}}{D}

\tau_w = \frac{8 \times 0.0035 \times 0.06}{0.004} = \mathbf{0.42 \text{ Pa}}


Problem 5 — Bernoulli: Constriction in Pipe

Given: Horizontal pipe, diameters D1=4D_1 = 4 cm, D2=2D_2 = 2 cm. v1=2v_1 = 2 m/s. Ideal fluid, no losses. Find v2v_2 and ΔP=P1P2\Delta P = P_1 - P_2. Blood ρ=1060\rho = 1060 kg/m³.

Solution:

Continuity: $v_2 = v_1 (A_1/A_2) = 2 \times (4/2)^2 = 2 \times 4 = \mathbf{8 \text{ m/s}}

Bernoulli (horizontal): $P_1 - P_2 = \frac{1}{2}\rho(v_2^2 - v_1^2)

\Delta P = \frac{1}{2}(1060)(64 - 4) = 530 \times 60 = \mathbf{31{,}800 \text{ Pa}} \approx \mathbf{239 \text{ mmHg}}

Pressure drops at constriction as velocity rises.


Problem 6 — Poiseuille Flow Rate

Given: Tube length L=0.10L = 0.10 m, radius r=1r = 1 mm, ΔP=1330\Delta P = 1330 Pa (10 mmHg), μ=0.003\mu = 0.003 Pa·s.

Solution:

Q=πr4ΔP8μL=π(103)4×13308×0.003×0.10Q=π×1012×13302.4×103=1.74×106 m3/s=1.74 mL/sQ = \frac{\pi r^4 \Delta P}{8\mu L} = \frac{\pi (10^{-3})^4 \times 1330}{8 \times 0.003 \times 0.10} Q = \frac{\pi \times 10^{-12} \times 1330}{2.4 \times 10^{-3}} = 1.74 \times 10^{-6} \text{ m}^3/\text{s} = \mathbf{1.74 \text{ mL/s}}

Problem 7 — Poiseuille: Radius Doubled

Given: Original flow rate Q0Q_0 through vessel. Radius doubles, all else constant. Find new QQ.

Solution:

If r2rr \to 2r, then Qr4Q \propto r^4:

Qnew=Q0×24=16Q0Q_{new} = Q_0 \times 2^4 = \mathbf{16 \, Q_0}

Problem 8 — Bernoulli: Venturi / Stenosis Pressure Drop

Given: Artery area reduces from A1=3A_1 = 3 cm² to A2=1A_2 = 1 cm². Upstream velocity v1=0.5v_1 = 0.5 m/s. ρ=1060\rho = 1060 kg/m³. Estimate ΔP\Delta P across stenosis (ideal).

Solution:

v2=0.5×3=1.5v_2 = 0.5 \times 3 = 1.5 m/s

ΔP=12ρ(v22v12)=530×(2.250.25)=530×2=1060 Pa8 mmHg\Delta P = \frac{1}{2}\rho(v_2^2 - v_1^2) = 530 \times (2.25 - 0.25) = 530 \times 2 = \mathbf{1060 \text{ Pa}} \approx \mathbf{8 \text{ mmHg}}

Problem 9 — Retinal Arteriole Reynolds Number

Given: D=0.07D = 0.07 mm = 7×1057 \times 10^{-5} m, V=4V = 4 cm/s = 0.04 m/s, ρ=1060\rho = 1060 kg/m³, μ=0.0035\mu = 0.0035 Pa·s.

Solution:

Re=1060×0.04×7×1050.0035=0.85Re = \frac{1060 \times 0.04 \times 7 \times 10^{-5}}{0.0035} = \mathbf{0.85}

Far below 2300 — no turbulence concern in retinal flow.


Problem 10 — Hydrostatic Blood Column (Worksheet)

Given: Maximum venous pressure ~120 mmHg. Open vertical tube connected to vein. Blood ρ=1040\rho = 1040 kg/m³.

Solution:

Convert: P=120 mmHg=120×133.3=15,996 PaP = 120 \text{ mmHg} = 120 \times 133.3 = 15{,}996 \text{ Pa}

h=Pρg=15,9961040×9.81=1.57 mh = \frac{P}{\rho g} = \frac{15{,}996}{1040 \times 9.81} = \mathbf{1.57 \text{ m}}

Blood would rise ~1.6 m — explains why IV lines must be managed carefully; also why nosebleed/shortness of breath at altitude (lower atmospheric pressure, relative vascular pressure effects).


Problem 11 — Hydraulic Jack (Pascal's Law, Worksheet)

Given: Small piston A1=0.8A_1 = 0.8 cm² = 8×1058 \times 10^{-5} m²; large piston A2=0.04A_2 = 0.04 m²; car weight W=13,000W = 13{,}000 N.

Solution:

Pascal: F1/A1=W/A2F_1 / A_1 = W / A_2

F1=WA1A2=13,000×8×1050.04=26 NF_1 = W \frac{A_1}{A_2} = 13{,}000 \times \frac{8 \times 10^{-5}}{0.04} = \mathbf{26 \text{ N}}

Small force lifts car — mechanical advantage A2/A1=500A_2/A_1 = 500. Raising car 2 m does not change required F1F_1 at equilibrium (hydrostatic); only fluid volume displaced changes.


Problem 12 — Mercury Manometer (Worksheet)

Given: Manometer Δh=10\Delta h = 10 mm Hg column; ρHg=13,600\rho_{Hg} = 13{,}600 kg/m³; Patm=100P_{atm} = 100 kPa. Duct connected to lower arm (fluid pushed down on duct side).

Solution:

ΔP=ρgΔh=13,600×9.81×0.01=1334 Pa\Delta P = \rho g \Delta h = 13{,}600 \times 9.81 \times 0.01 = 1334 \text{ Pa}

Duct pressure above atmospheric: Pduct=100,000+1334=101.3 kPaP_{duct} = 100{,}000 + 1334 = \mathbf{101.3 \text{ kPa}}.


Concept — Absolute Pressure vs Depth (Worksheet Part I)

Absolute pressure in liquid: Pabs=Patm+ρghP_{abs} = P_{atm} + \rho g h. Doubling depth does not double absolute pressure unless PatmP_{atm} is negligible — gauge pressure doubles, but absolute includes atmospheric baseline. At sea level, doubling depth from 10 m to 20 m in water: gauge doubles, absolute increases by less than 2×.


5. Equipment and Device Focus

Device / MethodFluid Mechanics PrincipleClinical Use
Venturi meterBernoulli + continuityIndustrial/medical flow measurement
Doppler echocardiographyBernoulli (ΔPv2\Delta P \propto v^2)Valve gradient, stenosis severity
Gorlin formulaBernoulli + empirical lossesEffective valve orifice area
Concentric cylinder viscometerShear stress / shear rateBlood viscosity measurement
SphygmomanometerPressure measurement (fluid statics)Arterial BP
Catheter pressure transducerDirect pressureIntracardiac, arterial pressures
SpirometerAirflow, airway resistance (Poiseuille)Lung function
Coronary stentRestores lumen radius → R1/r4R \propto 1/r^4Reduces flow resistance

Pressure measurement types:

  • Direct: catheter in vessel/chamber (gold standard, invasive).
  • Indirect: cuff sphygmomanometry (oscillometric or auscultatory).
  • Non-invasive derived: Doppler velocity → Bernoulli pressure estimate.

6. Practical Biomedical Engineering Perspective

6.1 Why Radius Matters More Than Length

Poiseuille's r4r^{-4} dependence means a 10% reduction in arterial radius doubles resistance (approximately). Coronary stenting that restores lumen diameter has disproportionate impact on perfusion. Vasoconstriction of arterioles is the body's primary short-term blood pressure control.

6.2 Stenosis: Engineering and Clinical View

Atherosclerotic plaque narrows lumen → local velocity increase (continuity) → pressure drop (Bernoulli) → murmur (turbulence) → reduced downstream perfusion. BME engineers designing stents or valve replacements must consider:

  • Restored effective orifice area (Gorlin)
  • Wall shear stress distribution (endothelial health)
  • Non-Newtonian blood behavior at low shear in expanded regions

6.3 Hematocrit and Device Design

Higher hematocrit → higher viscosity → higher resistance. Dialysis, CPB circuits, and blood pumps must account for apparent viscosity changes. Centrifugal pumps may induce hemolysis at high shear — a rheology-mechanics coupling problem.

6.4 Respiratory Surfactant Engineering

Premature infants lack surfactant → increased surface tension → alveolar collapse. Exogenous surfactant therapy is a direct application of Laplace's law and fluid surface mechanics.

6.5 Measurement Pitfalls

  • Assuming blood is Newtonian in all vessels (invalid in capillaries and post-stenotic regions).
  • Using Bernoulli without loss terms across long vascular segments.
  • Confusing viscosity (fluid property) with resistance (system property depending on geometry).

6.6 Aorta Branching — Clinical Anatomy Meets Continuity

The abdominal aorta at the L4 level bifurcates into the left and right common iliac arteries, which supply the lower limbs. Typical dimensions: aorta diameter 20–25 mm; each iliac ~10–12 mm. Cardiac output ~5 L/min at rest splits approximately equally in symmetric anatomy.

Engineering analysis steps for bifurcation problems:

  1. Compute parent flow: Q=AavaQ = A_a v_a.
  2. Apply conservation: Q=Q1+Q2Q = Q_1 + Q_2.
  3. If symmetric: Q1=Q2=Q/2Q_1 = Q_2 = Q/2.
  4. Solve branch velocities: vi=Qi/Aiv_i = Q_i / A_i.

When iliac stenosis reduces one branch area, continuity forces redistribution — higher velocity through the stenotic segment (Bernoulli pressure drop) with compensatory flow through collateral vessels. This is the mechanical basis of claudication assessment in peripheral arterial disease.

6.7 Capillary Exchange and Filtration (Starling Overview)

While detailed Starling mechanics cross into biotransport, capillary fluid mechanics appears on integrated exams. The net filtration pressure combines hydrostatic and oncotic pressures across the capillary wall. High capillary cross-sectional area (continuity from aorta) ensures low velocity, maximizing transit time for diffusive exchange. Fenestrated vs continuous capillaries affect permeability but not the continuity argument for low velocity.

6.8 Venous System as a Capacitance Vessel

Veins contain ~60–70% of total blood volume at rest despite lower velocity than arteries. Their thin, compliant walls act as a reservoir (Windkessel analog on the venous side). Venous return to the right atrium depends on:

  • Skeletal muscle pump: contraction squeezes veins; valves prevent backflow.
  • Respiratory pump: inspiration lowers thoracic pressure, drawing blood centrally.
  • Venous tone: sympathetic constriction reduces capacitance, increasing venous return.
  • Gravity: leg elevation assists return; prolonged standing pools blood in lower extremities.

Exam questions asking "main driving force in veins" expect recognition that arterial pressure alone does not fill the right heart — venous mechanisms are essential.


7. Frequently Tested Concepts

The following callouts cover frequently tested concepts on exit exams. Each callout gives the tested concept and the correct reasoning.


EXAM CALLOUT (biofluid-mechanics-tutorial-2024): Bernoulli describes pressure–velocity–elevation energy conservation — not viscosity directly. Continuity: flow rate constant in closed system with single inlet/outlet.

EXAM CALLOUT (worksheet): At high elevation, lower atmospheric pressure → relative increase in vascular transmural pressures → nosebleed risk; lower air density → same fan speed delivers lower mass flow rate (volume flow similar if speed identical).

EXAM CALLOUT (Q59, exit-0059): Thixotropic fluids are time-dependent non-Newtonian — viscosity changes with duration of shear. Bingham plastic, pseudo-plastic, and dilatant are time-independent. The odd one out is thixotropic.

EXAM CALLOUT (Q149, Q274, exit-0149, exit-0274): Velocity does NOT affect intrinsic fluid viscosity. Temperature, composition, and pressure (weakly) do. Do not confuse flow conditions with fluid properties.

EXAM CALLOUT (Q150, Q153, exit-0150, exit-0153): Poiseuille's law relates flow rate to vessel radius (Qr4Q \propto r^4). Flow rate increases dramatically (sixteen-fold when radius doubles) — exam wording may say "exponentially" meaning strong nonlinear dependence.

EXAM CALLOUT (Q151, Q262, Q263, exit-0151, exit-0262, exit-0263): Bernoulli: when velocity increases, pressure decreases (horizontal flow). In a constriction, fluid speeds up → pressure in constriction drops. Bernoulli relates pressure, velocity, and elevation (energy conservation).

EXAM CALLOUT (Q154, Q164, exit-0154, exit-0164): Large arteries under normal conditions: laminar flow. Re below critical value (~2300) → laminar.

EXAM CALLOUT (Q155, exit-0155): Reynolds number = ratio of inertial forces to viscous forces.

EXAM CALLOUT (Q156, exit-0156): Primary force driving blood flow: pressure gradient created by the heart.

EXAM CALLOUT (Q157, exit-0157): Arteries have the highest blood velocity (large flow, smaller total arterial area than capillary bed but individual arterial segments are fast). Capillaries have the lowest velocity.

EXAM CALLOUT (Q158, Q618, exit-0158, exit-0618): Red blood cells primarily determine blood viscosity and non-Newtonian behavior. Plasma alone is nearly Newtonian.

EXAM CALLOUT (Q160, exit-0160): Pulmonary surfactant prevents alveolar collapse during expiration by reducing surface tension.

EXAM CALLOUT (Q161, Q285, Q286, exit-0161, exit-0285, exit-0286): Gorlin equation calculates valve area. Valve area depends on pressure gradient, flow (CO), HR, and ejection time. Higher pressure gradient → higher flow through stenotic valve (for given area).

EXAM CALLOUT (Q162, exit-0162): No-slip condition: fluid velocity at a solid boundary is zero — fluid adheres to the wall.

EXAM CALLOUT (Q165, exit-0165): With constant pressure gradient across a tube (Poiseuille), velocity vr2v \propto r^2increasing diameter increases velocity. With constant flow rate (continuity), increasing diameter decreases velocity. Read the constraint.

EXAM CALLOUT (Q255, exit-0255): Viscosity affects resistance to flow (Poiseuille: RμR \propto \mu).

EXAM CALLOUT (Q257, exit-0257): Blood viscosity > water due to RBCs, plasma proteins, and temperature — often "all of the above" when offered.

EXAM CALLOUT (Q261, exit-0261): Kinematic viscosity ν=μ/ρ\nu = \mu / \rho (dynamic viscosity divided by density).

EXAM CALLOUT (Q265, Q288, exit-0265, exit-0288): Poiseuille: flow rate increases with pressure gradient, radius⁴, and decreases with viscosity and length. "All of the above" for factors affecting flow.

EXAM CALLOUT (Q277, exit-0277): Cardiovascular system does NOT primarily produce hormones (endocrine function). It transports nutrients, removes waste, and helps thermoregulation.

EXAM CALLOUT (Q282, exit-0282): Higher viscosity → lower flow rate (Poiseuille, fixed ΔP\Delta P).

EXAM CALLOUT (Q287, exit-0287): Valve geometry changes create resistance and alter turbulence — geometry affects flow.

EXAM CALLOUT (Q290, exit-0290): Venous return driven by skeletal muscle contraction, respiratory pump, and gravity — not primarily arterial pressure.

EXAM CALLOUT (Q291, exit-0291): Normal adult BP approximately 120/80 mmHg (range ~90/60 to 120/80 healthy).

EXAM CALLOUT (Q292, exit-0292): Stroke volume = blood ejected per beat. Cardiac output = HR × SV.

EXAM CALLOUT (Q293, exit-0293): Circulation analog: Ohm's law Q=ΔP/RQ = \Delta P / R. Not Boyle's or Charles's law.

EXAM CALLOUT (Q298, exit-0298): Density = mass/volume. Viscosity = resistance to shear deformation. Different properties.

EXAM CALLOUT (Q302, exit-0302): Casson model describes blood rheology (non-Newtonian). Not Poiseuille or Maxwell.

EXAM CALLOUT (Q303, exit-0303): Fåhræus–Lindqvist: apparent viscosity decreases in small vessels (<~300 µm) due to RBC migration toward vessel center. Not hematocrit decrease (that's Fåhræus effect).

EXAM CALLOUT (Q304, exit-0304): Atherosclerosis linked to shear rate / wall shear stress patterns at bifurcations.

EXAM CALLOUT (Q427, Q622, exit-0427, exit-0622): Vessel length does NOT affect blood viscosity. It affects resistance, not the fluid property μ\mu.

EXAM CALLOUT (Q464, exit-0464): Factors NOT affecting blood flow: look for irrelevant properties (e.g., blood type, unrelated hormones). Resistance, pressure gradient, and vessel radius always matter.

EXAM CALLOUT (Q619, exit-0619): Resistance inversely proportional to radius⁴ (Poiseuille). Not length (directly proportional) or viscosity (directly proportional).


8. Comparison Tables

8.1 Laminar vs Turbulent Flow

FeatureLaminarTurbulent
Particle motionParallel layers, orderlyChaotic, mixing eddies
Re (pipe)< 2300> 4000
Velocity profileParabolic (fully developed)Flat/blunt with mixing
PredictabilityHighLow
Energy lossLower (proportional to vv )Higher (proportional to v2v^2v3v^3 )
Blood contextNormal arteries, capillariesStenotic valves, severe murmurs
MixingPoorExcellent

8.2 Internal vs External Flow

FeatureInternal FlowExternal Flow
BoundaryFully bounded (pipe, vessel)Open stream over surface
ExamplesBlood in aorta, air in bronchiWind on wing, flow past stenosis
Key equationPoiseuille (laminar tube)Boundary layer theory
Velocity profileNo-slip at walls, max at centerDevelops from free stream to wall
Exam focusContinuity, Poiseuille, ReBernoulli lift applications

8.3 Compressible vs Incompressible Flow

FeatureIncompressibleCompressible
DensityConstantChanges with pressure
ExamplesBlood, water, low-speed air in bronchiHigh-speed gas, ultrasound contrast bubbles
ContinuityA1v1=A2v2A_1 v_1 = A_2 v_2ρ1A1v1=ρ2A2v2\rho_1 A_1 v_1 = \rho_2 A_2 v_2
Bernoulli useStandard form validModified for density changes
Bio defaultYes for bloodRespiratory high-flow exceptions

8.4 Arteries vs Veins vs Capillaries

PropertyArteriesCapillariesVeins
DirectionAway from heartConnect arterioles to venulesToward heart
Wall thicknessThick, elasticOne cell thickThin
PressureHigh (100+ mmHg systolic)Low (~20 mmHg)Low (~5–15 mmHg)
VelocityHighestLowestLow–moderate
Total cross-sectionModerateLargest (sum)Moderate
ValvesNo (aorta)NoYes
Primary functionDistributionExchangeCollection, return
Driving forceHeart pressurePressure gradientMuscle pump, gravity
Resistance roleConduitMinimalCapacitance (blood reservoir)

8.5 Newtonian vs Blood (Non-Newtonian)

PropertyNewtonian (water, plasma)Whole blood
μ\mu vs shear rateConstantVariable (shear-thinning)
Modelτ=μγ˙\tau = \mu \dot{\gamma}Casson, power-law
Primary causeMolecular cohesionRBC aggregation & deformation
Clinical relevancePlasma separation studiesPerfusion, hemolysis risk

9. Exam-Oriented Memory Aids

9.1 Equation Mnemonics

  • Continuity: "Same flow, fat pipe = slow" — constant QQ, bigger AA → smaller vv.
  • Bernoulli: "Speed up, squeeze down" — velocity up → pressure down.
  • Poiseuille: "Radius rules — r⁴" — radius dominates resistance.
  • Reynolds: "Big, fast, light, thin syrup = turbulent" — ρVD/μ\rho V D / \mu large → turbulent.
  • Ohm's law: "Flow follows pressure downhill through resistance."

9.2 Number Anchors

QuantityValue
Blood density~1060 kg/m³
Blood μ\mu (high shear)~0.003–0.004 Pa·s
Normal BP~120/80 mmHg
CO at rest~5 L/min
SV~70 mL
Aortic velocity~0.3 m/s
Capillary velocity~0.5 mm/s
Re critical (pipe)2300
Aorta Re~1000
Fåhræus–Lindqvistvessels < ~300 µm

9.3 "NOT" Answer Checklist

Question typeCommon NOT answer
Affects viscosity?Velocity, vessel length
Affects resistance?(not viscosity itself as geometry)
CV system function?Hormone production
Bernoulli describes?NOT viscosity–flow rate directly
Conservation law?NOT "conservation of pressure"

9.4 History Timeline (Blueprint)

EraFigureContribution
~2700 BCHuang TiEarly circulation writings
~400 BCHippocratesMedicine separated from magic
~300 BCAristotle, PraxagorasArteries vs veins distinction
1628William HarveyBlood recirculates, pumped by heart
1838PoiseuilleLaminar tube flow law
1890Otto FrankArterial pulse, pressure measurement
1883/1895ReynoldsLaminar–turbulent transition

10. Chapter Summary

Bio-fluid mechanics for the exit exam reduces to properties (density, viscosity, Newtonian vs non-Newtonian blood), conservation laws (continuity, Bernoulli with loss awareness, momentum), and pipe flow (Poiseuille, Reynolds, no-slip).

Blood is non-Newtonian because of red blood cells. The Casson model and Fåhræus–Lindqvist effect explain microvessel rheology. Do not confuse viscosity factors with Poiseuille resistance factors — vessel length affects resistance, not μ\mu.

Continuity conserves volume flow: A1v1=A2v2A_1 v_1 = A_2 v_2. Branching problems (aorta → iliac) split flow at bifurcations. Bernoulli trades pressure for kinetic energy: constriction → higher speed, lower pressure. Add loss terms for real vascular flows.

Poiseuille: Q=πr4ΔP/(8μL)Q = \pi r^4 \Delta P / (8\mu L). Radius is king (r4r^4). Ohm's law analogy: Q=ΔP/RQ = \Delta P / R. Reynolds number classifies laminar vs turbulent; physiological blood flow is predominantly laminar except pathology.

Cardiovascular distribution: arteries = highest velocity; capillaries = largest total area, lowest velocity; veins = low pressure, muscle-pump return. Gorlin equation estimates stenotic valve area. Surfactant prevents alveolar collapse.

Master the 41 callouts in Section 7 and the 9 worked problems in Section 4.7, then drill linked exit-NNNN items in the app.


11. Exam Practice Section

Basic Questions (10 MCQs)

1. Which property measures a fluid's resistance to shear deformation?

  • A) Density
  • B) Viscosity
  • C) Specific gravity
  • D) Surface tension

2. Kinematic viscosity is:

  • A) ρ/μ\rho / \mu
  • B) μ/ρ\mu / \rho
  • C) μ×ρ\mu \times \rho
  • D) ρg\rho g

3. The continuity equation for incompressible flow states:

  • A) Pressure is constant
  • B) AvA v is constant along a flow tube
  • C) Velocity is always constant
  • D) Density varies with velocity

4. According to Bernoulli's principle (horizontal, ideal flow), when velocity increases, pressure:

  • A) Increases
  • B) Decreases
  • C) Stays constant
  • D) Doubles

5. Which flow regime has Re < 2300 in a pipe?

  • A) Turbulent
  • B) Transitional only
  • C) Laminar
  • D) Irrotational

6. The no-slip condition means fluid at a solid wall has:

  • A) Maximum velocity
  • B) Zero velocity relative to the wall
  • C) Infinite shear stress
  • D) Slip parallel to the wall

7. Which blood component most strongly affects non-Newtonian behavior?

  • A) Platelets
  • B) White blood cells
  • C) Red blood cells
  • D) Electrolytes

8. Normal adult arterial blood pressure is approximately:

  • A) 80/40 mmHg
  • B) 120/80 mmHg
  • C) 160/100 mmHg
  • D) 200/120 mmHg

9. Which vessel type has the highest blood flow velocity?

  • A) Capillaries
  • B) Veins
  • C) Arteries
  • D) Venules

10. The Gorlin equation is used to calculate:

  • A) Blood viscosity
  • B) Valve area
  • C) Heart rate
  • D) Reynolds number

Intermediate Questions (10 MCQs)

11. Which factor does NOT affect intrinsic fluid viscosity?

  • A) Temperature
  • B) Composition
  • C) Velocity
  • D) Concentration

12. Poiseuille's law states QQ \propto:

  • A) r2r^2

  • B) r3r^3

  • C) r4r^4

  • D) 1/r1/r

13. If vessel radius doubles (constant ΔP\Delta P, LL, μ\mu), flow rate changes by:

  • A) 2×
  • B) 4×
  • C) 8×
  • D) 16×

14. Reynolds number is the ratio of:

  • A) Pressure to viscosity
  • B) Inertial to viscous forces
  • C) Density to velocity
  • D) Flow rate to area

15. Blood flow, pressure, and resistance relate by:

  • A) Boyle's law

  • B) Q=ΔP/RQ = \Delta P / R

  • C) Bernoulli only

  • D) F=maF = ma

16. The Fåhræus–Lindqvist effect is explained by:

  • A) Plasma protein denaturation
  • B) RBC migration toward vessel center
  • C) Turbulence in capillaries
  • D) Increased hematocrit in small vessels

17. Which model describes blood rheology with yield stress?

  • A) Hooke's law
  • B) Casson model
  • C) Fourier's law
  • D) Navier–Stokes (only)

18. Resistance to laminar flow is inversely proportional to:

  • A) Vessel length
  • B) Viscosity
  • C) Radius⁴
  • D) Pressure gradient

19. In a horizontal constriction, blood velocity ______ and pressure ______.

  • A) decreases, increases
  • B) increases, decreases
  • C) increases, increases
  • D) decreases, decreases

20. Primary driving force for arterial blood flow:

  • A) Gravity
  • B) Pressure gradient from the heart
  • C) Osmosis
  • D) Surface tension

Advanced Questions (10 MCQs)

21. Aorta diameter 2 cm, velocity 0.25 m/s. Splits equally into two 1 cm iliac arteries. Iliac velocity is:

  • A) 0.125 m/s
  • B) 0.25 m/s
  • C) 0.50 m/s
  • D) 1.0 m/s

22. Blood: ρ=1060\rho = 1060 kg/m³, μ=0.0035\mu = 0.0035 Pa·s, D=5D = 5 mm, V=0.1V = 0.1 m/s. Re ≈:

  • A) 15
  • B) 151
  • C) 1510
  • D) 15100

23. Which parameter does NOT affect blood viscosity?

  • A) Hematocrit
  • B) Temperature
  • C) Vessel length
  • D) Plasma proteins

24. Stroke volume is:

  • A) HR × CO
  • B) Blood ejected per beat
  • C) Blood flow per minute
  • D) End-diastolic volume only

25. Turbulent blood flow is most associated with:

  • A) Capillary exchange
  • B) Stenotic heart valve murmurs
  • C) Venous pooling
  • D) Lymphatic drainage

26. Bernoulli with viscous losses compared to ideal predicts:

  • A) Higher downstream pressure recovery
  • B) Lower downstream pressure recovery
  • C) Same velocity profile
  • D) No pressure drop at stenosis

27. Increasing hematocrit generally:

  • A) Decreases viscosity
  • B) Increases viscosity
  • C) Has no effect
  • D) Converts blood to Newtonian at all shear rates

28. Cardiovascular system does NOT:

  • A) Transport O₂ and nutrients
  • B) Remove CO₂ and wastes
  • C) Primarily produce insulin and cortisol
  • D) Participate in temperature regulation

29. Wall shear stress at the endothelial surface influences:

  • A) Bone remodeling only
  • B) Endothelial function and atherogenesis
  • C) Synovial fluid viscosity only
  • D) Alveolar surfactant production

30. At constant flow rate through a expanding vessel segment, velocity:

  • A) Increases with diameter
  • B) Decreases with diameter
  • C) Is independent of diameter
  • D) Always equals 0.3 m/s

Short Answer Questions (10)

31. State Newton's law of viscosity and define each term.

32. Explain the difference between dynamic and kinematic viscosity.

33. Why is blood classified as shear-thinning?

34. State the continuity equation for incompressible steady flow and explain its physical meaning.

35. Write Bernoulli's equation and state three assumptions for its validity.

36. Why does Poiseuille's law fail in the aorta despite laminar flow?

37. Define Reynolds number and give the laminar/turbulent thresholds for pipe flow.

38. Explain the no-slip condition and its effect on the velocity profile in a pipe.

39. What is the Fåhræus–Lindqvist effect and why does it occur?

40. State the Gorlin equation purpose and name three input variables.


Scenario-Based Questions (10)

41. A patient has severe aortic stenosis. Doppler shows velocity through the valve of 4 m/s. Explain why downstream tissue perfusion may be compromised despite high local velocity.

42. An athlete's descending aorta shows turbulent flow during maximal exercise. Explain using Reynolds number concepts.

43. A dialysis engineer increases catheter radius by 20%. Estimate the percent change in flow resistance (Poiseuille).

44. A premature infant receives exogenous surfactant. Explain the fluid mechanics rationale.

45. Blood viscosity is measured at 37°C and 25°C. Which reading is higher and why?

46. Two identical pipes carry water and blood at the same Re. Is the flow regime necessarily identical? Explain.

47. A stenotic artery reduces diameter by 50%. By what factor does Poiseuille resistance increase?

48. Why do veins have valves but arteries (except pulmonary/neck) generally do not?

49. A nurse elevates a patient's leg after varicose vein surgery. Explain the venous fluid mechanics benefit.

50. An engineer confuses vessel length as a factor affecting blood viscosity. Correct the error and explain the proper role of length.


Calculation Problems

51. Aorta radius 12 mm, velocity 0.28 m/s. Capillary velocity 4×1044 \times 10^{-4} m/s. Find total capillary cross-sectional area.

52. Pipe narrows from 6 cm to 3 cm diameter. Upstream velocity 1.5 m/s. Find downstream velocity (continuity).

53. Horizontal ideal pipe: v1=3v_1 = 3 m/s, P1=16P_1 = 16 kPa, v2=9v_2 = 9 m/s. ρ=1000\rho = 1000 kg/m³. Find P2P_2.

54. Tube: r=0.5r = 0.5 mm, L=0.05L = 0.05 m, ΔP=2000\Delta P = 2000 Pa, μ=0.004\mu = 0.004 Pa·s. Find QQ (Poiseuille).

55. ReRe calculation: D=3D = 3 mm, V=0.08V = 0.08 m/s, ρ=1060\rho = 1060 kg/m³, μ=0.003\mu = 0.003 Pa·s. Classify flow.

56. Resistance R0R_0 at radius r0r_0. Find RR when r=0.75r0r = 0.75 \, r_0.

57. Venturi: A1=5A_1 = 5 cm², A2=2A_2 = 2 cm², ΔP=1200\Delta P = 1200 Pa ideal horizontal. Find v1v_1 if v2=5v_2 = 5 m/s (work backward with continuity).

58. Cardiac output 5 L/min, HR 70 bpm. Find stroke volume.


Practice Solutions

Basic (1–10)

  1. B — Viscosity resists shear deformation.
  2. Bν=μ/ρ\nu = \mu/\rho.
  3. B — Incompressible continuity: A1v1=A2v2A_1 v_1 = A_2 v_2.
  4. B — Bernoulli trade-off: speed up → pressure down.
  5. C — Re < 2300 → laminar.
  6. B — No-slip: fluid at wall has zero velocity relative to wall.
  7. C — RBCs dominate non-Newtonian rheology.
  8. B — Normal ≈ 120/80 mmHg.
  9. C — Arteries have highest velocity.
  10. B — Gorlin → valve area.

Intermediate (11–20)

  1. C — Velocity does not change intrinsic μ\mu.
  2. C — Poiseuille: Qr4Q \propto r^4.
  3. D24=162^4 = 16.
  4. B — Re = inertial/viscous.
  5. B — Ohm's law analog for circulation.
  6. B — RBC axial migration lowers apparent viscosity in small tubes.
  7. B — Casson model includes yield stress for blood.
  8. CR1/r4R \propto 1/r^4.
  9. B — Constriction: velocity up, pressure down.
  10. B — Heart creates pressure gradient.

Advanced (21–30)

  1. CAava=2AiviA_a v_a = 2 A_i v_i; areas equal per iliac vs half aorta → same velocity 0.50 m/s.
  2. BRe=1060×0.1×0.005/0.0035151Re = 1060 \times 0.1 \times 0.005 / 0.0035 \approx 151.
  3. C — Length affects resistance, not viscosity.
  4. B — SV = volume per beat.
  5. B — Stenosis → turbulence → murmur.
  6. B — Losses reduce pressure recovery.
  7. B — Higher hematocrit → higher viscosity.
  8. C — Hormone production is endocrine, not primary CV function.
  9. B — Endothelial shear affects atherogenesis.
  10. B — Constant QQ: v=Q/Av = Q/A → larger diameter, lower velocity.

Short Answer (31–40) — Key Points

  1. τ=μdu/dy\tau = \mu \, du/dy; τ\tau = shear stress, μ\mu = dynamic viscosity, du/dydu/dy = velocity gradient.
  2. Dynamic μ\mu [Pa·s] resists shear; kinematic ν=μ/ρ\nu = \mu/\rho [m²/s] — used when gravity and viscosity compete.
  3. Apparent μ\mu decreases as shear rate increases due to RBC disaggregation and alignment.
  4. A1v1=A2v2A_1 v_1 = A_2 v_2; mass/volume flow conserved in steady incompressible flow without sources/sinks.
  5. P+12ρv2+ρgh=constP + \frac{1}{2}\rho v^2 + \rho g h = \text{const}; assumptions: steady, inviscid, incompressible, along streamline.
  6. Not fully developed, pulsatile, branched, non-Newtonian, elastic walls — Poiseuille assumes straight rigid tube, steady laminar Newtonian fully developed flow.
  7. Re=ρVD/μRe = \rho V D / \mu; laminar Re < 2300, turbulent Re > 4000.
  8. Fluid at wall has zero velocity; creates parabolic profile in laminar pipe flow.
  9. Apparent viscosity falls in tubes < ~300 µm because RBCs migrate to axial core, reducing effective resistance near walls.
  10. Estimates effective stenotic valve area from CO, HR, ejection time, and transvalvular pressure gradient.

Scenario (41–50) — Key Points

  1. High velocity at stenosis lowers pressure (Bernoulli); fixed cardiac output may not compensate — reduced perfusion.
  2. Exercise → higher VV and possibly larger effective diameter → Re increases → turbulence possible in aorta.
  3. R1/r4R \propto 1/r^4; r2=1.2r1r_2 = 1.2 r_1R2/R1=1/1.24=0.482R_2/R_1 = 1/1.2^4 = 0.482 — resistance drops ~52%.
  4. Surfactant lowers surface tension (Laplace) → prevents alveolar collapse at end-expiration.
  5. 25°C higher viscosity — lower temperature increases blood viscosity.
  6. Same Re → same regime classification if geometry comparable; different μ\mu and VV can give same Re.
  7. rr halved → RR increases by 1/(0.5)4=161/(0.5)^4 = 16 times.
  8. Veins operate at low pressure; valves prevent gravity backflow. Arteries have high pressure from heart.
  9. Elevation aids venous return by gravity assist to heart (reduces venous pooling).
  10. Length is in R=8μL/(πr4)R = 8\mu L/(\pi r^4) — affects resistance, not intrinsic μ\mu.

Calculations (51–58)

51. AC=π(0.012)2×0.28/(4×104)=π×1.44×104×700=0.316A_C = \pi (0.012)^2 \times 0.28 / (4 \times 10^{-4}) = \pi \times 1.44 \times 10^{-4} \times 700 = 0.316 m².

52. v2=v1(D1/D2)2=1.5×(6/3)2=1.5×4=6.0v_2 = v_1 (D_1/D_2)^2 = 1.5 \times (6/3)^2 = 1.5 \times 4 = 6.0 m/s.

53. ΔPkin=12ρ(v22v12)=500×(819)=36,000\Delta P_{kin} = \frac{1}{2}\rho(v_2^2 - v_1^2) = 500 \times (81 - 9) = 36{,}000 Pa. Thus P2=P136,000P_2 = P_1 - 36{,}000 Pa. For a physical solution with P2>0P_2 > 0, require P1>36P_1 > 36 kPa. Example: if P1=50P_1 = 50 kPa, then P2=14P_2 = 14 kPa. The kinetic pressure rise of 36 kPa from acceleration 3→9 m/s dominates — typical of high-speed constriction problems.

54. Q=π(5×104)4×2000/(8×0.004×0.05)=π×6.25×1014×2000/0.0016=2.45×107Q = \pi (5 \times 10^{-4})^4 \times 2000 / (8 \times 0.004 \times 0.05) = \pi \times 6.25 \times 10^{-14} \times 2000 / 0.0016 = 2.45 \times 10^{-7} m³/s = 0.245 mL/s.

55. Re=1060×0.08×0.003/0.003=84.8Re = 1060 \times 0.08 \times 0.003 / 0.003 = 84.8 → laminar.

56. R/R0=(r0/0.75r0)4=(4/3)4=3.16R/R_0 = (r_0/0.75 r_0)^4 = (4/3)^4 = 3.16 — resistance increases ~3.2×.

57. Continuity: v1=v2A2/A1=5×2/5=2v_1 = v_2 A_2/A_1 = 5 \times 2/5 = 2 m/s.

58. SV=CO/HR=5000/70=71.4SV = CO/HR = 5000/70 = 71.4 mL/beat.


Sources: data/summaries/telegram-b2-biofluid-chapter-*.json, materials/extracted/telegram/lee_waite_biofluid_mechanics_in_cardiovascular_sbook4you.txt, materials/extracted/telegram/biofluid-mechanics-and-biotrasportation.txt, materials/extracted/telegram/biofluid-mechanics-tutorial-q-a-2024.txt, materials/extracted/telegram/biofluid-mechanics-mock-exam.txt, MoE Revised Blueprint (2016 E.C.).